54. Spiral Matrix

2019-05-02

54. Spiral Matrix

Given a matrix of _m_ x _n_ elements (_m_ rows, _n_ columns), return all elements of the matrix in spiral order.

Example 1:

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Input:
[
 [ 1, 2, 3 ],
 [ 4, 5, 6 ],
 [ 7, 8, 9 ]
]
Output: [1,2,3,6,9,8,7,4,5]

Example 2:

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Input:
[
  [1, 2, 3, 4],
  [5, 6, 7, 8],
  [9,10,11,12]
]
Output: [1,2,3,4,8,12,11,10,9,5,6,7]

Code:

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class Solution(object):
    def spiralOrder(self, matrix):
        """
        :type matrix: List[List[int]]
        :rtype: List[int]
        """
        ret = []
        while matrix:
            ret += matrix.pop(0)
            if matrix and matrix[0]:
                for row in matrix:
                    ret.append(row.pop())
            if matrix:
                ret += matrix.pop()[::-1]
            if matrix and matrix[0]:
                for row in matrix[::-1]:
                    ret.append(row.pop(0))
        return ret
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def spiralOrder(self, matrix):
    return matrix and [*matrix.pop(0)] + self.spiralOrder([*zip(*matrix)][::-1])
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